How do you multiply $(j + -1k)(j + -1k)$ ?

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Answer 1 · 2017-07-06T19:01:24

See a solution process below:

We can rewrite this expression as:

$(j - k)(j - k) = (j - k)^2$

This is a special case of the quadratic:

$(a -b)^2 = a^2 - 2ab + b^2$

Substituting gives:

$(j - k)^2 = j^2 - 2jk + j^2$

How do you multiply (j + -1k)(j + -1k)(j + -1k)(j + -1k)?