How do you multiply $(k - 2) (k - 1)$ $(k - 2)(k - 1)$ ?

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Answer 1 · 2016-12-08T23:28:01

$k^{2} - 3 k + 2$ $k^2 - 3k + 2$

Use cross multiplication to multiply each term in the parenthesis on the left by each term within the parenthesis on the left:

$(k \cdot k - (1 \cdot k) - (2 \cdot k) + 2$ $(k*k - (1*k) - (2*k) + 2$

$k^{2} - 1 k - 2 k + 2$ $k^2 - 1k - 2k + 2$

Now combine like terms:

$k^{2} - 3 k + 2$ $k^2 - 3k + 2$

How do you multiply (k - 2)(k - 1)(k−2)(k−1)(k - 2)(k - 1)?