How do you multiply $(n + 3) (n + 6)$ $(n+3)(n+6)$ ?

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How do you multiply $(n + 3) (n + 6)$ $(n+3)(n+6)$ ?

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Answer 1 · 2016-05-10T02:19:40

$n^{2} + 9 n + 18$ $n^2+9n+18$

Explanation:

Given -

$(n + 3) (n + 6)$ $(n+3)(n+6)$
First take the $n$ $n$ in the right hand side expression.
Multiply the two terms on the left side.
Then take $6$ $6$ do the same
Simplify

$n^{2} + 3 n + 6 n + 18$ $n^2+3n+6n+18$
$n^{2} + 9 n + 18$ $n^2+9n+18$

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How do you multiply $(n + 3) (n + 6)$ $(n+3)(n+6)$ ?

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How do you multiply $(n + 3) (n + 6)$ $(n+3)(n+6)$ ?