How do you multiply $(n - 4) (n + 1)$ $(n-4)(n+1)$ ?

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Answer 1 · 2018-05-11T12:00:59

$n^{2} - 3 n - 4$ $n^2-3n-4$

$(n - 4) (n + 1)$ $(n-4)(n+1)$

= $n (n + 1) - 4 (n + 1)$ $n(n+1)-4(n+1)$

= $n^{2} + n - 4 n - 4$ $n^2+n-4n-4$

= $n^{2} - 3 n - 4$ $n^2-3n-4$

How do you multiply (n-4)(n+1)(n−4)(n+1)(n-4)(n+1)?