How do you multiply ${(p - 10)}^{2}$ $(p-10)^2$ ?

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Answer 1 · 2016-07-22T07:41:41

$p^{2} - 20 p + 100$ $p^2 - 20p + 100$

Rewrite as

$(p - 10) (p - 10)$ $(p-10)(p-10)$

Foil the bracket:

$p \cdot p - 10 p - 10 p + 100$ $p*p - 10p - 10p + 100$

$therefore p^2 - 20p + 100$

You could also do it with Pascal's triangle/Binomial theorem but for an exponent of 2 that's fairly unnecessary.

How do you multiply (p-10)^2(p−10)2(p-10)^2?