How do you multiply $\frac{r - 4}{5 r} = (\frac{1}{5 r}) + (1)$ $(r-4)/(5r)=(1/(5r)) + (1)$ ?

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Answer 1 · 2015-05-21T03:16:10

$\frac{r - 4}{5 r} = (\frac{1}{5 r}) + (1)$ $(r-4)/(5r)=(1/(5r)) + (1)$

$\frac{r - 4}{5 r} - \frac{1}{5 r} = 1 \times \frac{5 r}{5 r}$ $(r-4)/(5r) -1/(5r) = 1 xx (5r)/(5r)$

$\frac{r - 4}{5 r} - \frac{1}{5 r} = \frac{5 r}{5 r}$ $(r-4)/(5r) -1/(5r) = (5r)/(5r)$

$(r-4 -1)/cancel(5r) = (5r)/cancel(5r)$

$r-5 =5r$
$-5 =4r$

$r = -5/4$

How do you multiply (r-4)/(5r)=(1/(5r)) + (1)r−45r=(15r)+(1) (r-4)/(5r)=(1/(5r)) + (1)?