How do you multiply $\sqrt{2} \cdot [3 \cdot \sqrt{10} + 2 \cdot \sqrt{2}]$ $sqrt(2)[3sqrt(10) + 2*sqrt(2)]$ ?

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Answer 1 · 2015-06-23T01:01:57

$6 \sqrt{5} + 4$ $6sqrt(5)+4$

$\sqrt{2} [3 \cdot \sqrt{10} + 2 \cdot \sqrt{2}]$ $sqrt(2)[color(red)(3*sqrt(10))+ color(blue)(2*sqrt(2))]$

$= [\sqrt{2} \cdot 3 \cdot \sqrt{10}] + [\sqrt{2} \cdot 2 \cdot \sqrt{2}]$ $=[color(red)(sqrt(2)*3*sqrt(10))]+[color(blue)(sqrt(2)*2*sqrt(2))]$

$= [3 \cdot \sqrt{20}] + [2 \cdot \sqrt{4}]$ $=[color(red)(3*sqrt(20))]+[color(blue)(2*sqrt(4))]$

$= [3 \cdot 2 \sqrt{5}] + [2 \cdot 2]$ $=[color(red)(3*2sqrt(5))]+[color(blue)(2*2)]$

$= 6 \sqrt{5} + 4$ $=color(red)(6sqrt(5))+color(blue)(4)$

How do you multiply √2⋅[3⋅√10+2⋅√2]sqrt(2)*[3*sqrt(10) + 2*sqrt(2)]?