How do you multiply $\sqrt{2} \cdot \sqrt{6}$ $sqrt[2] * sqrt[6]$ ?

Question

6204 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2016-07-18T10:59:22

$2 \sqrt{3}$ $2sqrt(3)$

Write as $\sqrt{2} \times \sqrt{2 \times 3}$ $sqrt(2)xxsqrt(2xx3)$

Combining the roots

$\sqrt{2 \times 2 \times 3} \to \sqrt{2^{2} \times 3}$ $sqrt(2xx2xx3)-> sqrt(2^2xx3)$

Take $2^{2}$ $2^2$ outside the root

$2 \sqrt{3}$ $2sqrt(3)$

How do you multiply √2⋅√6sqrt[2] * sqrt[6]?