How do you multiply (sqrt6 +6c)(sqrt6 -6c) ? Algebra Radicals and Geometry Connections Multiplication and Division of Radicals 1 Answer George C. Jun 5, 2015 You can recognise this as being of the form (a+b)(a-b) = a^2-b^2 So: (sqrt(6)+6c)(sqrt(6)-6c) = (sqrt(6))^2-(6c)^2=6-36c^2 Answer link Related questions How do you simplify \frac{2}{\sqrt{3}}? How do you multiply and divide radicals? How do you rationalize the denominator? What is Multiplication and Division of Radicals? How do you simplify 7/(""^3sqrt(5)? How do you multiply (sqrt(a) +sqrt(b))(sqrt(a)-sqrt(b))? How do you rationalize the denominator for \frac{2x}{\sqrt{5}x}? Do you always have to rationalize the denominator? How do you simplify sqrt(5)sqrt(15)? How do you simplify (7sqrt(13) + 2sqrt(6))(2sqrt(3)+3sqrt(6))? See all questions in Multiplication and Division of Radicals Impact of this question 1311 views around the world You can reuse this answer Creative Commons License