How do you multiply ${(x^{2} - 1)}^{3}$ $(x^2-1)^3$ ?

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How do you multiply ${(x^{2} - 1)}^{3}$ $(x^2-1)^3$ ?

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Answer 1 · 2018-05-01T14:32:26

${(x^{2} - 1)}^{3} = x^{6} - 3 x^{4} + 3 x^{2} - 1$ $(x^2-1)^3=x^6-3x^4+3x^2-1$

Explanation:

${(a - b)}^{3} = a^{3} - 3 a^{2} b + 3 a b^{2} - b^{3}$ $(a-b)^3=a^3-3a^2b+3ab^2-b^3$

${(x^{2} - 1)}^{3} = {(x^{2})}^{3} - 3 {(x^{2})}^{2} + 3 x^{2} - 1 = x^{6} - 3 x^{4} + 3 x^{2} - 1$ $(x^2-1)^3=(x^2)^3-3(x^2)^2+3x^2-1=x^6-3x^4+3x^2-1$

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How do you multiply ${(x^{2} - 1)}^{3}$ $(x^2-1)^3$ ?

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How do you multiply ${(x^{2} - 1)}^{3}$ $(x^2-1)^3$ ?