How do you multiply $x^{\frac{2}{3}} (x^{\frac{1}{4}} - x)$ $x^(2/3)(x^(1/4) - x)$ ?

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How do you multiply $x^{\frac{2}{3}} (x^{\frac{1}{4}} - x)$ $x^(2/3)(x^(1/4) - x)$ ?

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Answer 1 · 2016-04-23T01:15:30

$= x^{\frac{2}{3}} \cdot x^{\frac{1}{4}} - x^{\frac{2}{3}} \cdot x^{1} = x^{\frac{8 + 3}{12}} - x^{\frac{2 + 3}{3}} = x^{\frac{11}{12}} - x^{\frac{5}{3}}$ $=x^(2/3)*x^(1/4)-x^(2/3)*x^1=x^((8+3)/12)-x^((2+3)/3)=x^(11/12)-x^(5/3)$

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How do you multiply $x^{\frac{2}{3}} (x^{\frac{1}{4}} - x)$ $x^(2/3)(x^(1/4) - x)$ ?

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