How do you multiply $(x^2+3x-5) (x^3+4x^2-3x+2)$ ?

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Answer 1 · 2015-08-23T11:09:11

$=color(blue)(x^5+7x^4+4x^3-27x^2+21x-10$

$color(blue)((x^2+3x−5))(x^3+4x^2−3x+2)$

$=color(blue)((x^2))(x^3+4x^2−3x+2) +color(blue)((3x))(x^3+4x^2−3x+2) + color(blue)((-5))(x^3+4x^2−3x+2)$

$=x^5+4x^4-3x^3+2x^2+color(blue)(3x^4+12x^3-9x^2+6x) -5x^3-20x^2+15x-10$

Adding like terms
$=color(blue)(x^5+7x^4+4x^3-27x^2+21x-10$

How do you multiply (x^2+3x-5) (x^3+4x^2-3x+2) (x^2+3x-5) (x^3+4x^2-3x+2) ?