How do you multiply $(x-2)(x+3)$ ?

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Answer 1 · 2015-08-12T10:36:03

$x^2 + x - 6$

(x - 2) ( x + 3)

steps
$x xx x$ = $x^2$

$x xx -2$ = -2x

$x xx 3$ = 3x

$-2 xx 3$ = -6

$x^2 +-2x +3x - 6$
$x^2 + x - 6$

How do you multiply (x-2)(x+3)(x-2)(x+3)?