How do you multiply ${(x + 3)}^{2}$ $(x + 3)^2$ ?

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Answer 1 · 2017-01-15T10:33:43

$= x^{2} + 6 x + 9$ $=x^2 +6x +9$

Note that the square means the base multiplied by itself..

$7^{2} = 7 \times 7 = 49$ $7^2 = 7xx7 = 49$

$x^{2} = x \times x$ $x^2 = x xx x$

${(x + 3)}^{2} = (x + 3) (x + 3)$ $(x+3)^2 = (x+3)(x+3)$

Each term in the first bracket is to be multiplied by each term in the second bracket.

$(x + 3) (x + 3)$ $(color(blue)(x)color(red)(+3))(x+3)$

$= x (x + 3) + 3 (x + 3)$ $=color(blue)(x)(x+3)color(red)(+3)(x+3)$

$= x^{2} + 3 x + 3 x + 9 \leftarrow$ $=color(blue)(x^2+3x) color(red)(+3x+9)" "larr$ there are 4 terms

$= x^{2} + 6 x + 9$ $=x^2 +6x +9$

DO not make the mistake of just squaring each to the terms.

${(x + 3)}^{2} \neq x^{2} + 9$ $(x+3)^2 != x^2 +9$

How do you multiply (x + 3)^2(x+3)2(x + 3)^2?