How do you multiply (x-3)^5(x−3)5?

1 Answer
bp
Aug 18, 2015

(x-3)^5= x^5- 15x^4 +90x^3 - 270x^2 +405x -243(x−3)5=x5−15x4+90x3−270x2+405x−243

Explanation:

Either use binomial theorem to get the answer or using the Pascal's triangle, the expansion of (x+y)^5 = x^5+5x^4y+10x^3y^2 +10x^2y^3 +5xy^4 +y^5(x+y)5=x5+5x4y+10x3y2+10x2y3+5xy4+y5
Now, substitute y= -3 to get,

(x-3)^5= x^5- 15x^4 +90x^3 - 270x^2 +405x -243(x−3)5=x5−15x4+90x3−270x2+405x−243

Related questions
See all questions in Multiplication of Polynomials by Binomials
Impact of this question
1417 views around the world
You can reuse this answer
Creative Commons License