How do you multiply $(x+3)(x-2)(6x-5)$ ?

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Answer 1 · 2016-10-27T04:20:20

$6x^3+x^2-41x+30$

Start by multiplying the first two then multiply the one you find by the third

$(x+3)(x-2)(6x-5)=(x^2+x-6)(6x-5)=6x^3-5x^2+6x^2-5x-36x+30=6x^3+x^2-41x+30$

Hope this helps :)

How do you multiply (x+3)(x-2)(6x-5)(x+3)(x-2)(6x-5)?