How do you multiply ${(x + 4)}^{2}$ $(x + 4)^2$ ?

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Answer 1 · 2016-04-28T12:18:23

$x^{2} + 8 x + 16$ $x^2+8x+16$

Write as: $(x + 4) (x + 4)$ $color(brown)((x+4)color(blue)((x+4)))$

Write as: $x (x + 4) + 4 (x + 4)$ $color(blue)(color(brown)(x)(x+4)color(brown)(+4)(x+4))$

Consider $x (x + 4)$ $x(x+4)$
Multiply everything inside the bracket be $x$ $x$
$x^{2} + 4 x$ $x^2+4x$

Consider $+ 4 (x + 4)$ $+4(x+4)$
Multiply everything inside the bracket by (+4)
$4 x + 16$ $4x+16$

Putting it all together

$(x^{2} + 4 x) + (4 x + 16)$ $(x^2+4x)+(4x+16)$

$x^{2} + 4 x + 4 x + 16$ $x^2+4x+4x+16$

$x^{2} + 8 x + 16$ $x^2+8x+16$

How do you multiply (x + 4)^2(x+4)2(x + 4)^2?