How do you multiply ${(x - 5)}^{2}$ $(x-5)^2$ ?

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How do you multiply ${(x - 5)}^{2}$ $(x-5)^2$ ?

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Answer 1 · 2018-03-18T01:49:46

$x^{2} - 10 x + 25$ $x^2-10x+25$

Explanation:

We got: ${(x - 5)}^{2}$ $(x-5)^2$

A fundamental rule in algebra is that ${(a - b)}^{2} = a^{2} - 2 a b + b^{2}$ $(a-b)^2=a^2-2ab+b^2$ , and ${(a + b)}^{2} = a^{2} + 2 a b + b^{2}$ $(a+b)^2=a^2+2ab+b^2$ .

But since we have a minus sign, we use the former one.

So, we plug in $a = x, b = 5$ $a=x,b=5$ , and we get:

$x^{2} - 2 \cdot x \cdot 5 + 5^{2}$ $x^2-2*x*5+5^2$

$= x^{2} - 10 x + 25$ $=x^2-10x+25$

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How do you multiply ${(x - 5)}^{2}$ $(x-5)^2$ ?

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How do you multiply ${(x - 5)}^{2}$ $(x-5)^2$ ?