How do you multiply $(x + 6) (x + 1)$ $(x+6)(x+1)$ ?

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How do you multiply $(x + 6) (x + 1)$ $(x+6)(x+1)$ ?

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Answer 1 · 2016-05-04T08:58:59

$x^{2} + 7 x + 6$ $x^2+7x+6$

Explanation:

The proper name for what I am about to show you is the property of being 'distributive'.

As a first step example: suppose we had $2 (x + 5)$ $2(x+5)$ then you multiply everything inside the bracket by 2 so you end up with $2 x + 10$ $2x+10$

Given $(x + 6) (x + 1)$ $" "color(blue)((x+6)color(brown)((x+1))$

Write as:

$x (x + 1) + 6 (x + 1)$ $color(blue)(x)color(brown)((x+1))color(blue)(+6color(brown)((x+1))" "$ This is the result of being 'distributive'.
$" "$ Notice the + follows the 6.

Multiply everything inside the brackets by what is outside it.

$x^{2} + x + 6 x + 6$ $x^2+x+6x+6$

$x^{2} + 7 x + 6$ $x^2+7x+6$

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How do you multiply $(x + 6) (x + 1)$ $(x+6)(x+1)$ ?

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How do you multiply $(x + 6) (x + 1)$ $(x+6)(x+1)$ ?