How do you multiply $(x + y + 3) (x + y - 4)$ $(x + y + 3)(x + y - 4)$ ?

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Answer 1 · 2016-08-25T18:50:34

The Expression $= x^{2} + 2 x y + y^{2} - x - y - 12$ $=x^2+2xy+y^2-x-y-12$ .

Letting $x + y = z$ $x+y=z$ , we find that,

The Expression $= (z + 3) (z - 4) = z (z - 4) + 3 (z - 4) = z^{2} - 4 z + 3 z - 12$ $=(z+3)(z-4)=z(z-4)+3(z-4)=z^2-4z+3z-12$

$= z^{2} - z - 12$ $=z^2-z-12$

Surrendering $z = x + y$ $z=x+y$ , we get,

The Expression $= {(x + y)}^{2} - x - y - 12$ $=(x+y)^2-x-y-12$

$= x^{2} + 2 x y + y^{2} - x - y - 12$ $=x^2+2xy+y^2-x-y-12$ .

How do you multiply (x + y + 3)(x + y - 4)(x+y+3)(x+y−4)(x + y + 3)(x + y - 4)?