How do you multiply $(y+4) (3y^4 -2y^2 +1)$ ?

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Answer 1 · 2015-08-04T06:13:22

$=color(blue)(3y^5 + 12y^4 −2y^3 −8y^2 + y + 4$

$color(blue)((y+4))(3y^4−2y^2+1)$

Here each term within the first bracket needs to be multiplied with all three terms of the second bracket.

$color(blue)((y)) * (3y^4−2y^2+1)+color(blue)(4) * (3y^4−2y^2+1)$

$=color(blue)((y)) * (3y^4−2y^2+1)+color(blue)(4) * (3y^4−2y^2+1)$

$=(3y^4*y−2y^2 * y +1*y)+ (3y^4*4 −2y^2*4+1*4)$

$=(3y^5−2y^3 +y)+ (12y^4 −8y^2+4)$

$=color(blue)(3y^5 + 12y^4 −2y^3 −8y^2 + y + 4$

How do you multiply (y+4) (3y^4 -2y^2 +1)(y+4) (3y^4 -2y^2 +1)?