How do you rationalize denominator $\frac{8}{\sqrt{5} + \sqrt{2}}$ $(8)/ (sqrt5+sqrt2)$ ?

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How do you rationalize denominator $\frac{8}{\sqrt{5} + \sqrt{2}}$ $(8)/ (sqrt5+sqrt2)$ ?

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Answer 1 · 2015-04-01T13:56:23

$\frac{8}{3}$ $8/3$ ( $\sqrt{5}$ $sqrt5$ - $\sqrt{2}$ $sqrt2$ )

Multiply the numerator and the denominator by the conjugate of $\sqrt{5}$ $sqrt5$ + $\sqrt{2}$ $sqrt2$ , which would be $\sqrt{5}$ $sqrt5$ - $\sqrt{2}$ $sqrt2$

On simplification we would have $\frac{8}{3}$ $8/3$ ( $\sqrt{5}$ $sqrt5$ - $\sqrt{2}$ $sqrt2$ )

[ ( $\sqrt{5}$ $sqrt5$ + $\sqrt{2}$ $sqrt2$ )( $\sqrt{5}$ $sqrt5$ - $\sqrt{2}$ $sqrt2$ ) = (5-2)=3]

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How do you rationalize denominator $\frac{8}{\sqrt{5} + \sqrt{2}}$ $(8)/ (sqrt5+sqrt2)$ ?

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How do you rationalize denominator $\frac{8}{\sqrt{5} + \sqrt{2}}$ $(8)/ (sqrt5+sqrt2)$ ?