How do you rationalize the denominator and simplify $\frac{15}{\sqrt{6} - 1}$ $15/(sqrt6-1)$ ?

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How do you rationalize the denominator and simplify $\frac{15}{\sqrt{6} - 1}$ $15/(sqrt6-1)$ ?

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Answer 1 · 2016-07-15T10:54:31

$3 (\sqrt{6} + 1)$ $3(sqrt6+1)$

Explanation:

$\frac{15}{\sqrt{6} - 1} = \frac{15 (\sqrt{6} + 1)}{(\sqrt{6} - 1) (\sqrt{6} + 1)} = \frac{15 (\sqrt{6} + 1)}{6 - 1} = 3 (\sqrt{6} + 1)$ $15/(sqrt6-1)= (15(sqrt6+1))/((sqrt6-1)(sqrt6+1))=(15(sqrt6+1))/(6-1)=3(sqrt6+1)$ [Ans]

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How do you rationalize the denominator and simplify $\frac{15}{\sqrt{6} - 1}$ $15/(sqrt6-1)$ ?

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How do you rationalize the denominator and simplify $\frac{15}{\sqrt{6} - 1}$ $15/(sqrt6-1)$ ?