How do you rationalize the denominator and simplify $\frac{2}{3 - \sqrt{7}}$ $2/(3-sqrt7)$ ?

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How do you rationalize the denominator and simplify $\frac{2}{3 - \sqrt{7}}$ $2/(3-sqrt7)$ ?

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Answer 1 · 2015-10-03T04:30:24

Refer to explanation

Explanation:

We multiply and divide with $3 + \sqrt{7}$ $3+sqrt7$ hence we have that

$\frac{2}{3 - \sqrt{7}} \cdot \frac{3 + \sqrt{7}}{3 - \sqrt{7}} = 2 \cdot \frac{3 + \sqrt{7}}{3^{2} - {(\sqrt{7})}^{2}} = 2 \cdot \frac{3 + \sqrt{7}}{9 - 7} = 3 + \sqrt{7}$ $2/(3-sqrt7)*(3+sqrt7)/(3-sqrt7)=2*(3+sqrt7)/(3^2-(sqrt7)^2)=2*(3+sqrt7)/(9-7)=3+sqrt7$

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How do you rationalize the denominator and simplify $\frac{2}{3 - \sqrt{7}}$ $2/(3-sqrt7)$ ?

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