How do you rationalize the denominator and simplify $\sqrt{\frac{5}{3}}$ $sqrt(5/3)$ ?

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How do you rationalize the denominator and simplify $\sqrt{\frac{5}{3}}$ $sqrt(5/3)$ ?

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Answer 1 · 2018-06-18T17:46:59

$\frac{\sqrt{15}}{3}$ $sqrt15/3$

Explanation:

$\sqrt{\frac{5}{3}}$ $sqrt(5/3)$

use the rule: $\sqrt{\frac{a}{b}} = \frac{\sqrt{a}}{\sqrt{b}}$ $sqrt(a/b) = sqrta/sqrtb$

$\frac{\sqrt{5}}{\sqrt{3}}$ $sqrt5/sqrt3$

now multiply by 1 in the form $\frac{a}{a}$ $a/a$ to rationalize:

$\frac{\sqrt{5}}{\sqrt{3}} \cdot \frac{\sqrt{3}}{\sqrt{3}} = \frac{\sqrt{15}}{\sqrt{9}} = \frac{\sqrt{15}}{3}$ $sqrt5/sqrt3 * sqrt3/sqrt3 = sqrt15/sqrt9=sqrt15/3$

Answer 2 · 2018-06-18T17:49:04

$\frac{\sqrt{15}}{3}$ $sqrt15/3$

Explanation:

$\sqrt{\frac{5}{3}} \Rightarrow \frac{\sqrt{5}}{\sqrt{3}}$ $sqrt(5/3) rArr sqrt5/sqrt3$

$\frac{\sqrt{5}}{\sqrt{3}} \times \frac{\sqrt{3}}{\sqrt{3}}$ $sqrt5/sqrt3 xx sqrt3/sqrt3$

$\Rightarrow = \frac{\sqrt{15}}{\sqrt{9}}$ $rArr =sqrt15/sqrt9$

$\Rightarrow \frac{\sqrt{15}}{3}$ $rArr sqrt15/3$

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How do you rationalize the denominator and simplify $\sqrt{\frac{5}{3}}$ $sqrt(5/3)$ ?

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How do you rationalize the denominator and simplify $\sqrt{\frac{5}{3}}$ $sqrt(5/3)$ ?