How do you rationalize the denominator and simplify $\frac{\sqrt{2}}{\sqrt{5}}$ $sqrt2/sqrt5$ ?

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Answer 1 · 2016-04-04T20:15:51

$\frac{\sqrt{10}}{5}$ $sqrt(10)/5$

Multiply by 1 and you do not change the inherent value. 1 can come in many forms. Foe example: $1 = \frac{\sqrt{5}}{\sqrt{5}}$ $1=sqrt(5)/sqrt(5)$

Multiply by 1 but in the form of $1 = \frac{\sqrt{5}}{\sqrt{5}}$ $1=sqrt(5)/sqrt(5)$ giving

$\frac{\sqrt{2}}{\sqrt{5}} \times \frac{\sqrt{5}}{\sqrt{5}}$ $sqrt(2)/(sqrt(5))xxsqrt(5)/sqrt(5)$

$= \frac{\sqrt{2} \sqrt{5}}{5}$ $=(sqrt(2)sqrt(5))/5$

$= \frac{\sqrt{2 \times 5}}{5}$ $=(sqrt(2xx5))/5$

$\frac{\sqrt{10}}{5}$ $sqrt(10)/5$

How do you rationalize the denominator and simplify √2√5sqrt2/sqrt5?