How do you rationalize the denominator and simplify $\frac{\sqrt{8}}{\sqrt{3}}$ $sqrt8/sqrt3$ ?

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Answer 1 · 2016-05-14T15:51:52

$\frac{2 \sqrt{6}}{3}$ $(2sqrt(6))/3$

Multiply by 1 but in the form of $1 = \frac{\sqrt{3}}{\sqrt{3}}$ $1=sqrt(3)/(sqrt(3))$

$\frac{\sqrt{8}}{\sqrt{3}} \times \frac{\sqrt{3}}{\sqrt{3}}$ $sqrt(8)/sqrt(3)xxsqrt(3)/sqrt(3)$

$\frac{\sqrt{8} \times \sqrt{3}}{3}$ $(sqrt(8)xxsqrt(3))/3$

$\frac{\sqrt{8 \times 3}}{3}$ $sqrt(8xx3)/3$

$\frac{\sqrt{2^{2} \times 2 \times 3}}{3}$ $sqrt(2^2xx2xx3)/3$

$\frac{2 \sqrt{6}}{3}$ $(2sqrt(6))/3$

How do you rationalize the denominator and simplify sqrt8/sqrt3√8√3sqrt8/sqrt3?