How do you rewrite with fractional exponents for $(root(3)(2))(root(3)(ab))$ ?

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Answer 1 · 2015-06-10T13:25:27

$(root(3)(2))(root(3)(ab)) = (2^(1/3))((ab)^(1/3))" or " (2ab)^(1/3)$

SInce $b^m*b*n*b*p = b^(m+n+p)$
then $b^(1/3) * b^(1/3) * b^(1/3) = b^1$

also $root(3)(b) * root(3)(b) * root(3)(b) = b^1$

So $root(3)(b)$ is the same as $b^(1/3)$

Replacing $b$ with $2$ and then with $ab$ lets us derive the given solution.

How do you rewrite with fractional exponents for (root(3)(2))(root(3)(ab))(root(3)(2))(root(3)(ab))?