How do you simplify ${(0.1 x + 0.4 y)}^{2}$ $(0.1x + 0.4y)^2$ ?

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How do you simplify ${(0.1 x + 0.4 y)}^{2}$ $(0.1x + 0.4y)^2$ ?

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Answer 1 · 2017-02-14T14:43:21

See the entire solution process below:

Explanation:

We can rewrite this expression as:

$(0.1 x + 0.4 y) (0.1 x + 0.4 y)$ $(0.1x + 0.4y)(0.1x + 0.4y)$

To multiply these two terms you multiply each individual term in the left parenthesis by each individual term in the right parenthesis.

$(0.1 x + 0.4 y) (0.1 x + 0.4 y)$ $(color(red)(0.1x) + color(red)(0.4y))(color(blue)(0.1x) + color(blue)(0.4y))$ becomes:

$(0.1 x \times 0.1 x) + (0.1 x \times 0.4 y) + (0.4 y \times 0.1 x) + (0.4 y \times 0.4 y)$ $(color(red)(0.1x) xx color(blue)(0.1x)) + (color(red)(0.1x) xx color(blue)(0.4y)) + (color(red)(0.4y) xx color(blue)(0.1x)) + (color(red)(0.4y) xx color(blue)(0.4y))$

$0.01 x^{2} + 0.04 x y + 0.04 x y + 0.16 y^{2}$ $0.01x^2 + 0.04xy + 0.04xy + 0.16y^2$

We can now combine like terms:

$0.01 x^{2} + (0.04 + 0.04) x y + 0.16 y^{2}$ $0.01x^2 + (0.04 + 0.04)xy + 0.16y^2$

$0.01 x^{2} + 0.08 x y + 0.16 y^{2}$ $0.01x^2 + 0.08xy + 0.16y^2$

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How do you simplify ${(0.1 x + 0.4 y)}^{2}$ $(0.1x + 0.4y)^2$ ?

1 Answer

Explanation:

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How do you simplify (0.1x + 0.4y)^2(0.1x+0.4y)2(0.1x + 0.4y)^2?

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How do you simplify ${(0.1 x + 0.4 y)}^{2}$ $(0.1x + 0.4y)^2$ ?