How do you simplify ${(\frac{1}{16})}^{- (\frac{1}{4})}$ $(1/16)^-(1/4)$ ?

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Answer 1 · 2018-05-24T15:57:41

$2$ $2$

we will use the following rules

$x^{- n} = \frac{1}{x^{n}}$ $x^(-n)=1/(x^n)$

$x^{\frac{1}{n}} = \sqrt[n]{x}$ $x^(1/n)=root(n)x$

${(\frac{1}{16})}^{- \frac{1}{4}}$ $(1/16)^(-1/4)$

$= {(\frac{16}{1})}^{\frac{1}{4}}$ $=(16/1)^(1/4)$

$= \sqrt[4]{16}$ $=root(4)(16)$

$= 2$ $=2$

How do you simplify (1/16)^-(1/4)(116)−(14)(1/16)^-(1/4)?