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How do you simplify $- {(\frac{1}{8})}^{- 1}$ $-(1/8)^-1$ ?

1 Answer

May 28, 2017

-8

Explanation:

$- {(\frac{1}{8})}^{- 1} = - \frac{1}{\frac{1}{8}} = - 8$ $-(1/8)^-1=- 1/(1/8)=-8$

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