How do you simplify ${(- (\frac{1}{8}))}^{- 1}$ $(-(1/8))^-1$ ?

Question

1775 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2017-02-10T17:38:49

$- 8$ $-8$

Consider the example $a^{- 1} = \frac{1}{a^{1}} = \frac{1}{a}$ $a^(-1) = 1/a^1=1/a$

But we have:

${(- (\frac{1}{8}))}^{- 1}$ $(-(1/8))^(-1)$ which is the same as $\frac{1}{{(- \frac{1}{8})}^{1}}$ $1/(-1/8)^1$

which is the same as: $\frac{1}{- (\frac{1}{8})}$ $" "1/-(1/8)$

which is the same as $- \frac{1}{\frac{1}{8}}$ $" "-1/(1/8)$

which is the same as $- 1 \times \frac{8}{1} = - 8$ $" " - 1xx8/1 = -8$

How do you simplify (−(18))−1(-(1/8))^-1?