How do you simplify $(-(1/8))^-2$ ?

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Answer 1 · 2016-09-01T15:15:59

$64$

Let's rewrite it in a slightly easier form first.

$(-(1/8))^-2 = ((-1)/8)^-2$

The negative index $rArr$ use the reciprocal of the base.

$(-8)^2$

Square of a negative number is a positive.

$(-8)^2 = 64$

How do you simplify (-(1/8))^-2(-(1/8))^-2?