How do you simplify 1/(sqrta+sqrtb)1√a+√b?

2 Answers
Alan N.
May 13, 2018

(sqrta-sqrtb)/(a-b)√a−√ba−b

Explanation:

Expression = 1/(sqrtx+sqrtb)=1√x+√b

Rationalise the denominator:

Expression = 1/(sqrtx+sqrtb) xx (sqrta - sqrtb)/ (sqrta - sqrtb)=1√x+√b×√a−√b√a−√b

= (sqrta-sqrtb)/(a-b)=√a−√ba−b

Dreamer.N
May 13, 2018

On simplification it would be(sqrta-sqrtb)/(a-b) √a−√ba−b

Explanation:

We have
1/(sqrta+sqrtb)1√a+√b
Multiplying and diving by sqrta-sqrtb√a−√b
We get (sqrta-sqrtb)/(a-b)√a−√ba−b which is the possible simplest form.

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