How do you simplify $(15 sqrt (8x ^16))/( 5 sqrt (2x ^4))$ ?

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Answer 1 · 2018-06-21T07:17:10

divide by 5

$[3sqrt(8x^16)]/[sqrt(2x^4)]$

square root the two $x$ terms

$[3x^8sqrt(8)]/[x^2sqrt(2)]$

cancel the $x^2$

$[3x^6sqrt(8)]/[sqrt(2)]$

$sqrt8=sqrt4xxsqrt2=2sqrt2$

so $[3x^6sqrt(8)]/[sqrt(2)]$ = $[3x^(6)2sqrt(2)]/[sqrt(2)] =[6x^6sqrt(2)]/[sqrt(2)]$

cancel the $sqrt2$

$6x^6$

How do you simplify (15 sqrt (8x ^16))/( 5 sqrt (2x ^4))(15 sqrt (8x ^16))/( 5 sqrt (2x ^4))?