How do you simplify $\frac{16 \sqrt{12}}{24 \sqrt{16}}$ $(16sqrt12)/(24sqrt16)$ ?

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How do you simplify $\frac{16 \sqrt{12}}{24 \sqrt{16}}$ $(16sqrt12)/(24sqrt16)$ ?

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Answer 1 · 2015-09-28T13:32:55

$\frac{\sqrt{3}}{3}$ $sqrt3/3$

Explanation:

By using laws of surds and consequent algebraic simplification, we may write this as

$\frac{16 \sqrt{4 \times 3}}{24 \sqrt{4} \times 4} = \frac{16 \cdot \sqrt{4} \cdot \sqrt{3}}{24 \cdot \sqrt{4} \cdot \sqrt{4}} = \frac{16 \times 2 \times \sqrt{3}}{24 \times 2 \times 2} = \frac{32 \sqrt{3}}{96} = \frac{\sqrt{3}}{3}$ $(16sqrt(4xx3))/(24sqrt4xx4)=(16*sqrt4*sqrt3)/(24*sqrt4*sqrt4)=(16xx2xxsqrt3)/(24xx2xx2)=(32sqrt3)/96=sqrt3/3$

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How do you simplify $\frac{16 \sqrt{12}}{24 \sqrt{16}}$ $(16sqrt12)/(24sqrt16)$ ?

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How do you simplify (16sqrt12)/(24sqrt16)16√1224√16(16sqrt12)/(24sqrt16)?

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How do you simplify $\frac{16 \sqrt{12}}{24 \sqrt{16}}$ $(16sqrt12)/(24sqrt16)$ ?