How do you simplify $(2^(1/4)*2^(1/3))^6$ ?

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Answer 1 · 2016-07-25T10:26:44

= $x^(7/2) = (sqrtx)^7$

There are 2 laws of indices which apply here.

$x^m xx x^n = x^(m+n)$ and $(x^m)^n = x^(mn)$

= $x^((7/12)xx6/1)$

= $x^(7/2) = (sqrtx)^7$

How do you simplify (2^(1/4)*2^(1/3))^6(2^(1/4)*2^(1/3))^6?