How do you simplify $\frac{2}{4 - \sqrt{6}}$ $2/(4-sqrt6)$ ?

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How do you simplify $\frac{2}{4 - \sqrt{6}}$ $2/(4-sqrt6)$ ?

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Answer 1 · 2016-04-24T05:35:22

It is

$\frac{2}{4 - \sqrt{6}} = \frac{2 \cdot (4 + \sqrt{6})}{(4 - \sqrt{6}) \cdot (4 + \sqrt{6})} = \frac{2 \cdot (4 + \sqrt{6})}{4^{2} - {(\sqrt{6})}^{2}} = 2 \cdot \frac{4 + \sqrt{6}}{16 - 6} = \frac{2}{10} \cdot (4 + \sqrt{6}) = \frac{1}{5} \cdot (4 + \sqrt{6})$ $2/(4-sqrt6)=[2*(4+sqrt6)]/[(4-sqrt6)*(4+sqrt6)]= [2*(4+sqrt6)]/(4^2-(sqrt6)^2)= 2*(4+sqrt6)/[16-6]=2/10*(4+sqrt6)=1/5*(4+sqrt6)$

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How do you simplify $\frac{2}{4 - \sqrt{6}}$ $2/(4-sqrt6)$ ?

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