How do you simplify $(2 + \sqrt{- 5}) (3 + \sqrt{- 7})$ $(2 + sqrt(-5))(3 + sqrt(-7))$ ?

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How do you simplify $(2 + \sqrt{- 5}) (3 + \sqrt{- 7})$ $(2 + sqrt(-5))(3 + sqrt(-7))$ ?

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Answer 1 · 2017-03-30T09:51:53

$(6 - \sqrt{35}) + i (2 \sqrt{7} + 3 \sqrt{5})$ $(6 - sqrt 35) + i(2 sqrt 7 + 3 sqrt 5)$

Explanation:

$(2 + i \sqrt{5}) (3 + i \sqrt{7}) = 6 + 2 i \sqrt{7} + 3 i \sqrt{5} - \sqrt{35}$ $(2 + i sqrt 5)(3 + i sqrt 7) = 6 + 2i sqrt 7 + 3i sqrt 5 - sqrt 35$

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How do you simplify $(2 + \sqrt{- 5}) (3 + \sqrt{- 7})$ $(2 + sqrt(-5))(3 + sqrt(-7))$ ?

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How do you simplify (2 + sqrt(-5))(3 + sqrt(-7))(2+√−5)(3+√−7)(2 + sqrt(-5))(3 + sqrt(-7))?

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How do you simplify $(2 + \sqrt{- 5}) (3 + \sqrt{- 7})$ $(2 + sqrt(-5))(3 + sqrt(-7))$ ?