How do you simplify $20^{\frac{1}{2}} \cdot 20^{\frac{1}{2}}$ $20^(1/2) *20^(1/2)$ ?

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How do you simplify $20^{\frac{1}{2}} \cdot 20^{\frac{1}{2}}$ $20^(1/2) *20^(1/2)$ ?

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Answer 1 · 2015-09-24T22:57:57

Have a look:

Explanation:

You can use the fact that:
$x^{a} \cdot x^{a} = x^{a + a}$ $x^a*x^a=x^(a+a)$
so you get:
$20^{\frac{1}{2}} \cdot 20^{\frac{1}{2}} = 20^{\frac{1}{2} + \frac{1}{2}} = 20^{1} = 20$ $20^(1/2)*20^(1/2)=20^(1/2+1/2)=20^1=20$

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How do you simplify $20^{\frac{1}{2}} \cdot 20^{\frac{1}{2}}$ $20^(1/2) *20^(1/2)$ ?

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How do you simplify $20^{\frac{1}{2}} \cdot 20^{\frac{1}{2}}$ $20^(1/2) *20^(1/2)$ ?