How do you simplify $256^{- \frac{7}{8}}$ $256^(-7/8)$ ?

Question

3446 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2015-04-08T06:19:54

$256^{- \frac{7}{8}}$ $color(red)(256^(-7/8)$

$= {({(256)}^{\frac{1}{8}})}^{- 7}$ $= ((256)^(1/8))^-7$

$= {(\sqrt[8]{256})}^{- 7}$ $= (root(8)256) ^ -7$

$= {(2)}^{- 7}$ $= (2)^-7$

$= \frac{1}{2^{7}}$ $= 1/(2^7)$

$= \frac{1}{128}$ $color(green)( = 1/ 128$

How do you simplify 256−78256^(-7/8)?