How do you simplify $27^{- \frac{1}{3}}$ $27^(-1/3)$ ?

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How do you simplify $27^{- \frac{1}{3}}$ $27^(-1/3)$ ?

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Answer 1 · 2016-12-23T03:54:14

1/3

Explanation:

We know, $a^{- 1} = \frac{1}{a}$ $a^-1 = 1/a$ [ laws of indices]

So, $27^{- \frac{1}{3}} = \frac{1}{{[27]}^{\frac{1}{3}}} = \frac{1}{{[3^{3}]}^{\frac{1}{3}}} = \frac{1}{3}$ $27^(-1/3) = 1/[27]^(1/3) = 1/[3^3]^(1/3) = 1/3$

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How do you simplify $27^{- \frac{1}{3}}$ $27^(-1/3)$ ?

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