How do you simplify $(27b)^(1/3) / (9b)^(-1/2)$ ?

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Answer 1 · 2015-09-04T06:41:16

$9b^(5/6)$

$((27b)^(1/3))/(9b)^(-1/2)$ = $(3b^(1/3))/(3^-1 b^(-1/2)$ = $9b^(1/2+1/3)$ = $9b^(5/6)$

How do you simplify (27b)^(1/3) / (9b)^(-1/2)(27b)^(1/3) / (9b)^(-1/2)?