How do you simplify $(27x^6y^12)^(2/3)$ ?

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Answer 1 · 2015-11-01T20:43:35

$9x^4y^8$

Using laws of exponents we get

$(27x^6y^12)^(2/3)=27^(2/3)(x^6)^(2/3)(y^12)^(2/3)$

$=root(3)(27^2)*x^(12/3)*y^(24/3)$

$=9x^4y^8$

How do you simplify (27x^6y^12)^(2/3)(27x^6y^12)^(2/3)?