How do you simplify $(2 \sqrt{10}) (4 \sqrt{15})$ $(2sqrt10)(4sqrt15)$ ?

Question

How do you simplify $(2 \sqrt{10}) (4 \sqrt{15})$ $(2sqrt10)(4sqrt15)$ ?

1 Answer

Impact of this question

1620 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2017-05-25T00:57:43

See a solution process below:

Explanation:

First, rewrite the expression as:

$(2 \cdot 4) (\sqrt{10} \cdot \sqrt{15}) \Rightarrow 8 (\sqrt{10} \cdot \sqrt{15})$ $(2 * 4)(sqrt(10) * sqrt(15)) => 8(sqrt(10) * sqrt(15))$

Next, use this rule for exponents to combine the radicals:

$\sqrt{a} \cdot \sqrt{b} = \sqrt{a \cdot b}$ $sqrt(a) * sqrt(b) = sqrt(a * b)$

$8 (\sqrt{10} \cdot \sqrt{15}) \Rightarrow 8 \sqrt{10 \cdot 15} \Rightarrow 8 \sqrt{150}$ $8(sqrt(10) * sqrt(15)) => 8sqrt(10 * 15) => 8sqrt(150)$

We can rewrite this as:

$8 \sqrt{25 \cdot 6}$ $8sqrt(25 * 6)$

We can use the above rule for radicals in reverse to simplify the radical term:

$\sqrt{a \cdot b} = \sqrt{a} \cdot \sqrt{b}$ $sqrt(a * b) = sqrt(a) * sqrt(b)$

$8 (\sqrt{25 \cdot 6}) = 8 (\sqrt{25} \cdot \sqrt{6}) \Rightarrow 8 (5 \cdot \sqrt{6}) \Rightarrow$ $8(sqrt(25 * 6)) = 8(sqrt(25) * sqrt(6)) => 8(5 * sqrt(6)) =>$

$(8 \cdot 5) \sqrt{6} \Rightarrow$ $(8 * 5)sqrt(6) =>$

$40 \sqrt{6}$ $40sqrt(6)$

Science

Math

Humanities

... and beyond

How do you simplify $(2 \sqrt{10}) (4 \sqrt{15})$ $(2sqrt10)(4sqrt15)$ ?

1 Answer

Explanation:

Related questions

Impact of this question

Science

Math

Humanities

... and beyond

How do you simplify (2√10)(4√15)(2sqrt10)(4sqrt15)?

1 Answer

Explanation:

Related questions

Impact of this question

How do you simplify $(2 \sqrt{10}) (4 \sqrt{15})$ $(2sqrt10)(4sqrt15)$ ?