How do you simplify $\frac{2 \sqrt{4}}{8 \sqrt{3}}$ $(2sqrt4)/(8sqrt3)$ ?

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How do you simplify $\frac{2 \sqrt{4}}{8 \sqrt{3}}$ $(2sqrt4)/(8sqrt3)$ ?

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Answer 1 · 2016-09-04T03:26:48

$\frac{\sqrt{3}}{6}$ $sqrt3/6$

Explanation:

$\frac{2 \sqrt{4}}{8 \sqrt{3}} = \frac{2 \times 2}{8 \sqrt{3}} = \frac{1}{2 \sqrt{3}}$ $(2sqrt4)/(8sqrt3) = (2xx2)/(8sqrt3) = 1/(2sqrt3)$

$\frac{1}{2 \sqrt{3}} \times \frac{\sqrt{3}}{\sqrt{3}} = \frac{\sqrt{3}}{2 \times 3} = \frac{\sqrt{3}}{6}$ $1/(2sqrt3)xxsqrt3/sqrt3 = sqrt3/(2xx3) =sqrt3/6$

Answer 2 · 2016-09-04T07:42:31

$\frac{\sqrt{3}}{6}$ $(sqrt(3)) / (6)$

Explanation:

We have: $\frac{2 \sqrt{4}}{8 \sqrt{3}}$ $(2 sqrt(4)) / (8 sqrt(3))$

$= \frac{2 \cdot 2}{8 \sqrt{3}}$ $= (2 cdot 2) / (8 sqrt(3))$

$= \frac{4}{8 \sqrt{3}}$ $= (4) / (8 sqrt(3))$

$= \frac{1}{2 \sqrt{3}}$ $= (1) / (2 sqrt(3))$

Now, let's rationalise the denominator by multiplying both the numerator and denominator by $\sqrt{3}$ $sqrt(3)$ :

$= \frac{1}{2 \sqrt{3}} \cdot \frac{\sqrt{3}}{\sqrt{3}}$ $= (1) / (2 sqrt(3)) cdot (sqrt(3)) / (sqrt(3))$

$= \frac{\sqrt{3}}{2 \cdot 3}$ $= (sqrt(3)) / (2 cdot 3)$

$= \frac{\sqrt{3}}{6}$ $= (sqrt(3)) / (6)$

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