How do you simplify $(2x^(3/4)) (5y^(4/6)) (x^(5/4)) (3y^(-2/6))$ ?

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Answer 1 · 2016-04-08T16:48:31

$30x^2root(3)y$

Put together all the like terms - that is, multiply the $x$ 's together, the $y$ 's, and the actual numbers.

$x^(3/4) * x^(5/4) = x^(3/4 + 5/4) = x^(8/4) = x^2$
$y^(4/6) * y^(-2/6) = y^(4/6 - 2/6) = y^(1/3)$
$2 * 5 * 3 = 30$

and put it back together again,

$30x^2root(3)y$

How do you simplify (2x^(3/4)) (5y^(4/6)) (x^(5/4)) (3y^(-2/6))(2x^(3/4)) (5y^(4/6)) (x^(5/4)) (3y^(-2/6))?