How do you simplify $3^{- 1} \cdot 5^{- 2}$ $3^-1*5^-2$ ?

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Answer 1 · 2017-01-03T21:52:16

See full explanation of the simplification process below

To simplify this expression we first need to use one of the rules for exponents:

$x^{a} = \frac{1}{x^{- a}}$ $color(red)(x^a = 1/x^(-a))$

Using this rule we can rewrite this problem as:

$\frac{1}{3^{- - 1} \cdot 5^{- - 2}} = \frac{1}{3^{1} \cdot 5^{2}}$ $1/(3^(- -1)* 5^(- -2)) = 1/(3^1*5^2)$

We know $x^{1} = x$ $x^1 = x$ so we can rewrite this as"

$\frac{1}{3 \times 5 \times 5} = \frac{1}{75}$ $1/(3 xx 5 xx 5) = 1/75$

How do you simplify 3−1⋅5−23^-1*5^-2?