How do you simplify $\frac{3}{\sqrt{6} - \sqrt{3}}$ $3 / (sqrt6 -sqrt3)$ ?

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How do you simplify $\frac{3}{\sqrt{6} - \sqrt{3}}$ $3 / (sqrt6 -sqrt3)$ ?

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Answer 1 · 2016-08-01T12:31:48

$= \sqrt{6} + \sqrt{3}$ $=sqrt6+sqrt3$

Explanation:

$\frac{3}{\sqrt{6} - \sqrt{3}}$ $3/(sqrt6-sqrt3)$
Multiplying numerator and denominator by $(\sqrt{6} + \sqrt{3})$ $(sqrt6+sqrt3)$
we get
$3 \frac{\sqrt{6} + \sqrt{3}}{(\sqrt{6} + \sqrt{3}) (\sqrt{6} - \sqrt{3})}$ $3(sqrt6+sqrt3)/((sqrt6+sqrt3)(sqrt6-sqrt3)$
$= 3 \frac{\sqrt{6} + \sqrt{3}}{6 - 3}$ $=3(sqrt6+sqrt3)/(6-3)$
$= 3 \frac{\sqrt{6} + \sqrt{3}}{3}$ $=3(sqrt6+sqrt3)/3$
$= \sqrt{6} + \sqrt{3}$ $=sqrt6+sqrt3$

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How do you simplify $\frac{3}{\sqrt{6} - \sqrt{3}}$ $3 / (sqrt6 -sqrt3)$ ?

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