How do you simplify $- 3 \sqrt{7 r^{3}} \cdot 6 \sqrt{7 r^{2}}$ $-3sqrt(7r^3)*6sqrt(7r^2)$ ?

Question

1586 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2017-12-13T09:06:10

$= - 126 r^{2} \sqrt{r}$ $=-126r^2sqrtr$

You can combine the two square roots into one because they are being multiplied.

$- 3 \sqrt{7 r^{3}} \times 6 \sqrt{7 r^{2}}$ $-3sqrt(7r^3) xx 6sqrt(7r^2)$

$= - 18 \sqrt{7^{2} r^{5}}$ $= -18sqrt(7^2r^5)$

$= - 18 \times 7 r^{2} \sqrt{r}$ $=-18 xx 7r^2sqrtr$

$= - 126 r^{2} \sqrt{r}$ $=-126r^2sqrtr$

How do you simplify −3√7r3⋅6√7r2-3sqrt(7r^3)*6sqrt(7r^2)?